time and work Model Questions & Answers, Practice Test for ssc cgl tier 1 2023
ssc cgl tier 1 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
Ratio Proportion & Partnership
Averages
Percentages
Profit & Loss
Time & Work
Time & Distance
Simple Interest & Compound Interest
Mensuration: Area & Volumes
Algebraic Expressions
Linear Equations
Squareroots & Cuberoots
A alone would take 8 days more to complete the job than if both A and B would together. If B worked alone, he took 4$1/2$ days more to complete the job than A and B worked together. What time would they take if both A and B worked together ?
Answer: (d)
Let if both A and B work together, they take x days.
∴ (A + B)'s days's work = $1/x$ th work
A's 1 day's work = $1/{x + 8}$ th work
's 1 day's work = $1/{x + 9/2}$ th work.
Now, $1/{x + 8} + 2/{2x + 9} = 1/x$
⇒ x(2x + 9 + 2x + 16) = (x + 8)(2x + 9)
⇒ $4x^2 + 25x = 2x^2 + 25x + 72$
$x^2$ = 36⇒x = 6 days
Alternate Method :-
A and B together finish the work in $(√ {8 × 9/2})$ = 6 days
If a man walks to his office at 3/4 of his usual rate, he reaches office 1/3 of an hour later than usual. What is his usual time to reach office.
Answer: (c)
If new speed is $a/b$ of original speed, then
usual time × $(b/a - 1)$ change in time
&there4 usual time × $(4/3 - 1) = 1/3$
⇒ usual time = $1/3$ × 3 = 1 hr
If a bus travels 160 km in 4 hours and a train travels 320 km in 5 hours at uniform speeds, then what is the ratio of the distances travelled by them in one hour ?
Answer: (c)
Distance covered by a bus in 4 hours = 160 km.
∴ Distance covered by a bus in 1 hour = ${160}/4$ = 40 km
Further, Distance covered by a train in 5 hours = 320 km
∴ Distance covered by a train in 1 hour = ${320}/5$ = 64 km
Required ratio = ${40}/{64} = 5/8$ = 5 : 8
A and B together can do a piece of work in 12 days and B and C finish the same work together in 16 days. After A has worked on it for 5 days and B for 7 days, C finishes it in 13 days. In how many days will C alone be able to finish the work ?
Answer: (c)
Work done by (A + B) in 1 day = $1/{12}$
Work done by (B + C) in 1 day = $1/{16}$
Let C finishes the work in x days.
Then, work done by C in 1 day = $1/x$
We have, A's 5 days' work + B's 7days' work + C's 13 days' work = 1
or [(A + B)'s 5 days' + (B + C)' s 2 days' + C's 11 days'] work = 1
or $5/{12} + 2/{16} + {11}/x$ = 1 or x = 24 days
A can do a work in 9 days. If B is 50% more efficient than A, then in how many days can B do the same work alone ?
Answer: (b)
Units of work done by A in 1 day = $1/9$
Units of work done by B in 1 day = ${15}/{90}$ = $1/6$
Hence, B alone will complete the work in 6 days.
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