time and work Model Questions & Answers, Practice Test for ssc cgl tier 1 2023

Question :6

A alone would take 8 days more to complete the job than if both A and B would together. If B worked alone, he took 4$1/2$ days more to complete the job than A and B worked together. What time would they take if both A and B worked together ?

Answer: (d)

Let if both A and B work together, they take x days.

∴ (A + B)'s days's work = $1/x$ th work

A's 1 day's work = $1/{x + 8}$ th work

's 1 day's work = $1/{x + 9/2}$ th work.

Now, $1/{x + 8} + 2/{2x + 9} = 1/x$

⇒ x(2x + 9 + 2x + 16) = (x + 8)(2x + 9)

⇒ $4x^2 + 25x = 2x^2 + 25x + 72$

$x^2$ = 36⇒x = 6 days

Alternate Method :-

A and B together finish the work in $(√ {8 × 9/2})$ = 6 days

Question :7

If a man walks to his office at 3/4 of his usual rate, he reaches office 1/3 of an hour later than usual. What is his usual time to reach office.

Answer: (c)

If new speed is $a/b$ of original speed, then

usual time × $(b/a - 1)$ change in time

&there4 usual time × $(4/3 - 1) = 1/3$

⇒ usual time = $1/3$ × 3 = 1 hr

Question :8

If a bus travels 160 km in 4 hours and a train travels 320 km in 5 hours at uniform speeds, then what is the ratio of the distances travelled by them in one hour ?

Answer: (c)

Distance covered by a bus in 4 hours = 160 km.

∴ Distance covered by a bus in 1 hour = ${160}/4$ = 40 km

Further, Distance covered by a train in 5 hours = 320 km

∴ Distance covered by a train in 1 hour = ${320}/5$ = 64 km

Required ratio = ${40}/{64} = 5/8$ = 5 : 8

Question :9

A and B together can do a piece of work in 12 days and B and C finish the same work together in 16 days. After A has worked on it for 5 days and B for 7 days, C finishes it in 13 days. In how many days will C alone be able to finish the work ?

Answer: (c)

Work done by (A + B) in 1 day = $1/{12}$

Work done by (B + C) in 1 day = $1/{16}$

Let C finishes the work in x days.

Then, work done by C in 1 day = $1/x$

We have, A's 5 days' work + B's 7days' work + C's 13 days' work = 1

or [(A + B)'s 5 days' + (B + C)' s 2 days' + C's 11 days'] work = 1

or $5/{12} + 2/{16} + {11}/x$ = 1 or x = 24 days

Question :10

A can do a work in 9 days. If B is 50% more efficient than A, then in how many days can B do the same work alone ?

Answer: (b)

Units of work done by A in 1 day = $1/9$

Units of work done by B in 1 day = ${15}/{90}$ = $1/6$

Hence, B alone will complete the work in 6 days.

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